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X^2+5X=329
We move all terms to the left:
X^2+5X-(329)=0
a = 1; b = 5; c = -329;
Δ = b2-4ac
Δ = 52-4·1·(-329)
Δ = 1341
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1341}=\sqrt{9*149}=\sqrt{9}*\sqrt{149}=3\sqrt{149}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{149}}{2*1}=\frac{-5-3\sqrt{149}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{149}}{2*1}=\frac{-5+3\sqrt{149}}{2} $
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